[PATCH] dmr/amdgpu: Fix wrongly unref of BO

[Xie, AlexBin]

Hi David,


When amdgpu_bo_reserve return errors, we cannot release the BO. This is not a memory leak. General speaking, memory leak is unnoticed and unintentional.


The caller of function amdgpu_vram_scratch_fini ignores the return error value...


The "memory leak" is not caused by my patch. It is caused because reserving BO fails.


This patch only aim to make function amdgpu_vram_scratch_fini behave correctly.


To follow up, we can add a warning message when amdgpu_bo_reserve error happens in a different patch.


If function call amdgpu_bo_reserve is changed to uninterruptible, this changes driver behaviour. Without a substantial issue, I would be cautious for such a change.


Thanks,

Alex Bin Xie

________________________________
From: Zhou, David(ChunMing)
Sent: Monday, April 17, 2017 10:38 PM
To: Xie, AlexBin; amd-gfx at lists.freedesktop.org
Subject: Re: [PATCH] dmr/amdgpu: Fix wrongly unref of BO



On 2017年04月17日 22:54, Xie, AlexBin wrote:

Hi David,


Thanks for the comments. However, please have look at amdgpu_bo_reserve definition.

static inline int amdgpu_bo_reserve(struct amdgpu_bo *bo, bool no_intr)

Ah, this is a wired wrapper for ttm_bo_reserve.



When we call this function like the following:

         r = amdgpu_bo_reserve(adev->vram_scratch.robj, false);
The false means interruptible.


On the other hand,  when amdgpu_bo_reserve function return error, why do we unref BO without kunmap and unpin the BO? This is wrong implementation when amdgpu_bo_reserve return any error.

Yeah, I see your mean, it's in driver un-loading, How about changing to no interruptible? Your patch will make a memleak if bo_reserve fails, but it seems not matter. I have no strong preference.

Regards,
David Zhou


Thanks,
Alex Bin Xie

________________________________
From: Zhou, David(ChunMing)
Sent: Friday, April 14, 2017 12:00 AM
To: Xie, AlexBin; amd-gfx at lists.freedesktop.org<mailto:amd-gfx at lists.freedesktop.org>
Subject: Re: [PATCH] dmr/amdgpu: Fix wrongly unref of BO



On 2017年04月14日 05:34, Alex Xie wrote:
> According to comment of amdgpu_bo_reserve, amdgpu_bo_reserve
> can return with -ERESTARTSYS. When this function was interrupted
> by a signal, BO should not be unref. Otherwise the BO might be
> released while is kmapped and pinned, or BO MIGHT be deref
> multiple times, etc.
         r = amdgpu_bo_reserve(adev->vram_scratch.robj, false);
we have specified interruptible to false, so -ERESTARTSYS isn't possible
here.

Thanks,
David Zhou
>
> Change-Id: If76071a768950a0d3ad9d5da7fcae04881807621
> Signed-off-by: Alex Xie <AlexBin.Xie at amd.com><mailto:AlexBin.Xie at amd.com>
> ---
>   drivers/gpu/drm/amd/amdgpu/amdgpu_device.c | 2 +-
>   1 file changed, 1 insertion(+), 1 deletion(-)
>
> diff --git a/drivers/gpu/drm/amd/amdgpu/amdgpu_device.c b/drivers/gpu/drm/amd/amdgpu/amdgpu_device.c
> index 53996e3..1dcc2d1 100644
> --- a/drivers/gpu/drm/amd/amdgpu/amdgpu_device.c
> +++ b/drivers/gpu/drm/amd/amdgpu/amdgpu_device.c
> @@ -355,8 +355,8 @@ static void amdgpu_vram_scratch_fini(struct amdgpu_device *adev)
>                amdgpu_bo_kunmap(adev->vram_scratch.robj);
>                amdgpu_bo_unpin(adev->vram_scratch.robj);
>                amdgpu_bo_unreserve(adev->vram_scratch.robj);
> +             amdgpu_bo_unref(&adev->vram_scratch.robj);
>        }
> -     amdgpu_bo_unref(&adev->vram_scratch.robj);
>   }
>
>   /**


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