[Intel-gfx] [PATCH v2] drm/i915/tv: avoid possible division by zero
Andi Shyti
andi.shyti at linux.intel.com
Mon Jul 24 17:35:27 UTC 2023
On Tue, Jul 18, 2023 at 09:32:17AM +0800, Su Hui wrote:
> Clang warning: drivers/gpu/drm/i915/display/intel_tv.c:
> line 991, column 22 Division by zero.
> Assuming tv_mode->oversample=1 and (!tv_mode->progressive)=1,
> then division by zero will happen.
>
> Fixes: 1bba5543e4fe ("drm/i915: Fix TV encoder clock computation")
> Signed-off-by: Su Hui <suhui at nfschina.com>
> ---
> drivers/gpu/drm/i915/display/intel_tv.c | 2 +-
> 1 file changed, 1 insertion(+), 1 deletion(-)
>
> diff --git a/drivers/gpu/drm/i915/display/intel_tv.c b/drivers/gpu/drm/i915/display/intel_tv.c
> index 36b479b46b60..f59553f7c132 100644
> --- a/drivers/gpu/drm/i915/display/intel_tv.c
> +++ b/drivers/gpu/drm/i915/display/intel_tv.c
> @@ -988,7 +988,7 @@ intel_tv_mode_to_mode(struct drm_display_mode *mode,
> const struct tv_mode *tv_mode,
> int clock)
> {
> - mode->clock = clock / (tv_mode->oversample >> !tv_mode->progressive);
> + mode->clock = clock / tv_mode->oversample << !tv_mode->progressive;
but this does not provide the same value. Try with:
8 / (2 >> 1)
and
8 / 2 << 1
They are definitely different.
The real check could be:
if (!(tv_mode->oversample >> 1))
return ...
But first I would check if that's actually possible.
Andi
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