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<b><a class="bz_bug_link
bz_status_NEW "
title="NEW - Radeon: heavy r300 performance drop regression between 11.x and 19.x"
href="https://bugs.freedesktop.org/show_bug.cgi?id=110781#c25">Comment # 25</a>
on <a class="bz_bug_link
bz_status_NEW "
title="NEW - Radeon: heavy r300 performance drop regression between 11.x and 19.x"
href="https://bugs.freedesktop.org/show_bug.cgi?id=110781">bug 110781</a>
from <span class="vcard"><a class="email" href="mailto:u9vata@gmail.com" title="Richard Thier <u9vata@gmail.com>"> <span class="fn">Richard Thier</span></a>
</span></b>
<pre>In the assert problem this is the domain and flag meanings in case of only my
hack is in place:
domain(6) == RADEON_DOMAIN_GTT(2) | RADEON_DOMAIN_VRAM(4)
flags(1) == RADEON_FLAG_GTT_WC (1 << 0)
So I get -1 even if I "outcomment" this check in radeon_get_heap_index(..):
/* Resources with interprocess sharing don't use any winsys allocators.
if (!(flags & RADEON_FLAG_NO_INTERPROCESS_SHARING))
return -1;*/
There is a switch statement in this function where they switch based on the
domain parameter:
switch (domain) {
case RADEON_DOMAIN_VRAM:
...
case RADEON_DOMAIN_GTT:
...
default:
break;
}
return -1;
I suspect we return -1 here because we go into the "default" case. I think that
is right because domain is: 6 == 2 | 4 == GTT+VRAM at the same time.
Maybe once it was meaningful to have both GTT (is that GART?) and VRAM at the
same time being or-ed together but not anymore?
I will try to add a hack to make the domain always just VRAM to see what
happens... I know that is bad, but just for the analysis.</pre>
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