Alignment in allocator question

[Carlos Rafael Giani]

On 2014-03-04 03:54, Nicolas Dufresne wrote:
> Le lundi 03 mars 2014 à 22:47 +0100, Carlos Rafael Giani a écrit :
>> and also read up again that align is actually a bitmask.
>
> I didn't check the code you are referring, but alignment is usually a 
> shift, not a mask.
>
> Nicolas
>
>
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Well yes. Inside the code, the align value is used for both the 
allocation size and the shifting of the pointer, as usual. The odd thing 
is that the documentation describes it as a bitmask, and the code tests 
that it is a power of two (with the (align&(align-1))==0 check). This is 
what I find so strange. Why this complicated solution? Why not just a 
plain alignment value?
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