[igt-dev] [PATCH i-g-t 1/3] runner/executor: Make sure that intervals_left is always initialized

Petri Latvala petri.latvala at intel.com
Thu Jun 20 12:33:36 UTC 2019


On Thu, Jun 20, 2019 at 03:29:00PM +0300, Arkadiusz Hiler wrote:
> intervals_left got initialized only when when we had a timeout exceeding
> watchdog capabilities, meaning we had to use multiple shorter intervals
> 
> by moving intervals_left = timeout_intervals down we are always
> initializing it
> 
> Cc: Petri Latvala <petri.latvala at intel.com>
> Signed-off-by: Arkadiusz Hiler <arkadiusz.hiler at intel.com>

Reviewed-by: Petri Latvala <petri.latvala at intel.com>


> ---
>  runner/executor.c | 3 ++-
>  1 file changed, 2 insertions(+), 1 deletion(-)
> 
> diff --git a/runner/executor.c b/runner/executor.c
> index 7e5fbe8f..bce4d420 100644
> --- a/runner/executor.c
> +++ b/runner/executor.c
> @@ -493,7 +493,6 @@ static int monitor_output(pid_t child,
>  			if (wd_timeout - wd_extra < 0)
>  				wd_extra = wd_timeout / 2;
>  			timeout_intervals = timeout / (wd_timeout - wd_extra);
> -			intervals_left = timeout_intervals;
>  			timeout /= timeout_intervals;
>  
>  			if (settings->log_level >= LOG_LEVEL_VERBOSE) {
> @@ -504,6 +503,8 @@ static int monitor_output(pid_t child,
>  		}
>  	}
>  
> +	intervals_left = timeout_intervals;
> +
>  	while (outfd >= 0 || errfd >= 0 || sigfd >= 0) {
>  		struct timeval tv = { .tv_sec = timeout };
>  
> -- 
> 2.21.0
> 


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