[Intel-gfx] [PATCH 05/12] drm/i915: Clear VLV_IER around irq processing

Chris Wilson chris at chris-wilson.co.uk
Thu Apr 14 08:32:30 UTC 2016


On Thu, Apr 14, 2016 at 11:22:48AM +0300, Ville Syrjälä wrote:
> On Wed, Apr 13, 2016 at 09:53:38PM +0100, Chris Wilson wrote:
> > On Wed, Apr 13, 2016 at 09:19:51PM +0300, ville.syrjala at linux.intel.com wrote:
> > > +		/*
> > > +		 * Theory on interrupt generation, based on empirical evidence:
> > > +		 *
> > > +		 * x = ((VLV_IIR & VLV_IER) ||
> > > +		 *      (((GT_IIR & GT_IER) || (GEN6_PMIIR & GEN6_PMIER)) &&
> > > +		 *       (VLV_MASTER_IER & MASTER_INTERRUPT_ENABLE)));
> > > +		 *
> > > +		 * A CPU interrupt will only be raised when 'x' has a 0->1 edge.
> > > +		 * Hence we clear MASTER_INTERRUPT_ENABLE and VLV_IER to
> > > +		 * guarantee the CPU interrupt will be raised again even if we
> > > +		 * don't end up clearing all the VLV_IIR, GT_IIR, GEN6_PMIIR
> > > +		 * bits this time around.
> > 
> > Following this logic, we want to enable MASTER_IER before VLV_IER such
> > that we get an immediate irq if there is a residual VLV_IIR.
> 
> The order between master irq enable and VLV_IIR shouldn't matter. They
> are totally independent of each other. Master irq enable is for GT,
> VLV_IER is for display. We just have to make sure both of them are
> going to be zero simultaneously, which will guarantee that the CPU
> interrupt generation logic will see x==0 at that point.

There is no flow from VLV_IER to VLV_MASTER_IER ?

Hmm, I guess it only matters if the interrupt is raised on the leading
edge versus the level. I presumed we had only edge triggered interrupts,
that is the signal is sent fom VLV_IIR & VLV_IER once and will not
result in an interrupt unless VLV_MASTER_IER is enabled.
-Chris

-- 
Chris Wilson, Intel Open Source Technology Centre


More information about the Intel-gfx mailing list