[Intel-gfx] [PATCH 20/41] drm/i915: Replace priolist rbtree with a skiplist

Tvrtko Ursulin tvrtko.ursulin at linux.intel.com
Thu Jan 28 16:42:44 UTC 2021


On 28/01/2021 16:26, Chris Wilson wrote:
> Quoting Tvrtko Ursulin (2021-01-28 15:56:19)
>> On 25/01/2021 14:01, Chris Wilson wrote:
>>> diff --git a/drivers/gpu/drm/i915/i915_priolist_types.h b/drivers/gpu/drm/i915/i915_priolist_types.h
>>> index bc2fa84f98a8..1200c3df6a4a 100644
>>> --- a/drivers/gpu/drm/i915/i915_priolist_types.h
>>> +++ b/drivers/gpu/drm/i915/i915_priolist_types.h
>>> @@ -38,10 +38,36 @@ enum {
>>>    #define I915_PRIORITY_UNPREEMPTABLE INT_MAX
>>>    #define I915_PRIORITY_BARRIER (I915_PRIORITY_UNPREEMPTABLE - 1)
>>>    
>>> +#ifdef CONFIG_64BIT
>>> +#define I915_PRIOLIST_HEIGHT 12
>>> +#else
>>> +#define I915_PRIOLIST_HEIGHT 11
>>> +#endif
>>
>> I did not get this. On one hand I could think pointers are larger on
>> 64-bit so go for fewer levels, if size was a concern. But on the other
>> hand 32-bit is less important these days, definitely much less as a
>> performance platform. So going for less memory use => worse performance
>> on a less important platform, which typically could be more memory
>> constrained? Not sure I see it as that important either way to be
>> distinctive but a comment would satisfy me.
> 
> Just aligned to the cacheline. The struct is 128B on 64b and 64B on 32b.
> On 64B, we will scale to around 16 million requests in flight and 4
> million on 32b. Which should be enough.
> 
> If we shrunk 64b to a 64B node, we would only scale to 256 requests
> which limit we definitely will exceed.

Ok thanks, pouring it into a comment is implied.

> 
>>>    struct i915_priolist {
>>>        struct list_head requests;
>>
>> What would be on this list? Request can only be on one at a time, so I
>> was thinking these nodes would have pointers to list of that priority,
>> rather than lists themselves. Assuming there can be multiple nodes of
>> the same priority in the 2d hierarcy. Possibly I don't understand the
>> layout.
> 
> A request is only on one list (queue, active, hold). But we may still
> have more than one request at the same deadline, though that will likely
> be limited to priority-inheritance and timeslice deferrals.
> 
> Since we would need pointer to the request, we could only reclaim a
> single pointer here, which is not enough to warrant reducing the overall
> node size. And while there is at least one user of request->sched.link,
> the list maintenance will still be incurred. Using request->sched.link
> remains a convenient interface.

Lost you.

Is the data structure like this and I will limit to priorities for 
simplicity:

    Level1:	[-1]------------->[1]
    Level0: 	[-1]---->[0]----->[1]
[SENTINEL]

Each of the boxes is struct i915_priolist?

Sentinel contains pointers to first i915_priolist for each level. Or 
maybe it could contain just a single pointer to highest level (most 
sparse) list.

And then each box is i915_priolist, single linked to next, in order.

But it should also have a single pointer for down, or up (or both)? I 
don't understand why you have up to "max levels" pointers in each.

And each box should then contain a pointer to a list of requests. I 
cannot each have it's own list since there are duplicates.

But obviously I am understanding something way wrong.

> 
>>
>>> -     struct rb_node node;
>>>        int priority;
>>> +
>>> +     int level;
>>> +     struct i915_priolist *next[I915_PRIOLIST_HEIGHT];
>>
>> Does every node need maximum height or you could allocated depending on
>> current height?
> 
> Every slab allocation here is a power of 2, so there are only a few
> different options that are worthwhile (on 64b the only other choice is
> [4], unless you want to go larger to [28]). It did not feel like enough
> benefit to justify the extra code.
> 
>>> -static void assert_priolists(struct i915_sched_engine * const se)
>>> -{
>>> -     struct rb_node *rb;
>>> -     long last_prio;
>>> -
>>> -     if (!IS_ENABLED(CONFIG_DRM_I915_DEBUG_GEM))
>>> -             return;
>>> -
>>> -     GEM_BUG_ON(rb_first_cached(&se->queue) !=
>>> -                rb_first(&se->queue.rb_root));
>>> -
>>> -     last_prio = INT_MAX;
>>> -     for (rb = rb_first_cached(&se->queue); rb; rb = rb_next(rb)) {
>>> -             const struct i915_priolist *p = to_priolist(rb);
>>> -
>>> -             GEM_BUG_ON(p->priority > last_prio);
>>> -             last_prio = p->priority;
>>> -     }
>>> +     root->prng = next_pseudo_random32(root->prng);
>>> +     return  __ffs(root->prng) / 2;
>>
>> Where is the relationship to I915_PRIOLIST_HEIGHT? Feels root->prng %
>> I915_PRIOLIST_HEIGHT would be more obvious here unless I am terribly
>> mistaken. Or at least put a comment saying why the hack.
> 
> HEIGHT is the maximum possible for our struct. skiplists only want to
> increment the height of the tree one step at a time. So we choose a level
> with decreasing probability, and then limit that to the maximum height of
> the current tree + 1, clamped to HEIGHT.
> 
> You might notice that unlike traditional skiplists, this uses a

That's optimistic, that I would notice that. I'll stick to the basics 
for now. :)

Regards,

Tvrtko

> probability of 0.25 for each additional level. A neat trick discovered by
> Con Kolivas (I haven't found it mentioned elsewhere) as the cost of the
> extra level (using P=.5) is the same as the extra chain length with
> P=.25. So you can scale to higher number of requests by packing more
> requests into each level.
> 
> So that is split between randomly choosing a level and then working out
> the height of the node.
> 
>>>    static struct list_head *
>>>    lookup_priolist(struct intel_engine_cs *engine, int prio)
>>>    {
>>> +     struct i915_priolist *update[I915_PRIOLIST_HEIGHT];
>>>        struct i915_sched_engine * const se = &engine->active;
>>> -     struct i915_priolist *p;
>>> -     struct rb_node **parent, *rb;
>>> -     bool first = true;
>>> -
>>> -     lockdep_assert_held(&engine->active.lock);
>>> -     assert_priolists(se);
>>> +     struct i915_priolist_root *root = &se->queue;
>>> +     struct i915_priolist *pl, *tmp;
>>> +     int lvl;
>>>    
>>> +     lockdep_assert_held(&se->lock);
>>>        if (unlikely(se->no_priolist))
>>>                prio = I915_PRIORITY_NORMAL;
>>>    
>>> +     for_each_priolist(pl, root) { /* recycle any empty elements before us */
>>> +             if (pl->priority >= prio || !list_empty(&pl->requests))
>>> +                     break;
>>> +
>>> +             i915_priolist_advance(root, pl);
>>> +     }
>>> +
>>>    find_priolist:
>>> -     /* most positive priority is scheduled first, equal priorities fifo */
>>> -     rb = NULL;
>>> -     parent = &se->queue.rb_root.rb_node;
>>> -     while (*parent) {
>>> -             rb = *parent;
>>> -             p = to_priolist(rb);
>>> -             if (prio > p->priority) {
>>> -                     parent = &rb->rb_left;
>>> -             } else if (prio < p->priority) {
>>> -                     parent = &rb->rb_right;
>>> -                     first = false;
>>> -             } else {
>>> -                     return &p->requests;
>>> -             }
>>> +     pl = &root->sentinel;
>>> +     lvl = pl->level;
>>> +     while (lvl >= 0) {
>>> +             while (tmp = pl->next[lvl], tmp->priority >= prio)
>>> +                     pl = tmp;
>>> +             if (pl->priority == prio)
>>> +                     goto out;
>>> +             update[lvl--] = pl;
>>>        }
>>>    
>>>        if (prio == I915_PRIORITY_NORMAL) {
>>> -             p = &se->default_priolist;
>>> +             pl = &se->default_priolist;
>>> +     } else if (!pl_empty(&root->sentinel.requests)) {
>>> +             pl = pl_pop(&root->sentinel.requests);
>>>        } else {
>>> -             p = kmem_cache_alloc(global.slab_priorities, GFP_ATOMIC);
>>> +             pl = kmem_cache_alloc(global.slab_priorities, GFP_ATOMIC);
>>>                /* Convert an allocation failure to a priority bump */
>>> -             if (unlikely(!p)) {
>>> +             if (unlikely(!pl)) {
>>>                        prio = I915_PRIORITY_NORMAL; /* recurses just once */
>>>    
>>> -                     /* To maintain ordering with all rendering, after an
>>> +                     /*
>>> +                      * To maintain ordering with all rendering, after an
>>>                         * allocation failure we have to disable all scheduling.
>>>                         * Requests will then be executed in fifo, and schedule
>>>                         * will ensure that dependencies are emitted in fifo.
>>> @@ -260,18 +304,103 @@ lookup_priolist(struct intel_engine_cs *engine, int prio)
>>>                }
>>>        }
>>>    
>>> -     p->priority = prio;
>>> -     INIT_LIST_HEAD(&p->requests);
>>> +     pl->priority = prio;
>>> +     INIT_LIST_HEAD(&pl->requests);
>>>    
>>> -     rb_link_node(&p->node, rb, parent);
>>> -     rb_insert_color_cached(&p->node, &se->queue, first);
>>> +     lvl = random_level(root);
>>> +     if (lvl > root->sentinel.level) {
>>> +             if (root->sentinel.level < I915_PRIOLIST_HEIGHT - 1) {
>>> +                     lvl = ++root->sentinel.level;
>>
>> root->sentinel.level is maximum currently populated height? So if
>> random_level said insert at 4 but there are currently only 2 levels,
>> height will grow by one only?
> 
> Yes. The idea is keep the number of next[] as small as possible for the
> number of nodes in the tree. (Since the height of the tree is the
> constant overhead in list traversal.)
> 
>>> +                     update[lvl] = &root->sentinel;
>>> +             } else {
>>> +                     lvl = I915_PRIOLIST_HEIGHT - 1;
>>
>> But if maximum level already has been reached then this branch does not
>> set anything to update[],
> 
> at the next level.
> 
>> relying on the while loop earlier in the
>> function has populated it? How should I think of the update array?
> 
> The update[] is the array of nodes just before the position we need to
> insert. So update[] needs only be the height of the tree at that time,
> and if we decide to grow the tree, update[height] will be the root node,
> as we will be the first in that level.
> -Chris
> 


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