[PATCH v5 8/8] drm/i915/gvt: let timeslice usage control vGPU scheduling

Tian, Kevin kevin.tian at intel.com
Wed Mar 29 03:37:35 UTC 2017


> From: Ping Gao
> Sent: Tuesday, March 28, 2017 2:48 PM
> 
> The timeslice usage will determine vGPU whether has chance to schedule or
> not at every vGPU switch checkpoint.

"The timeslice usage determines whether a vGPU still has chance to be
scheduled. Move to take this new scheme in scheduling policy."

> 
> Signed-off-by: Ping Gao <ping.a.gao at intel.com>
> ---
>  drivers/gpu/drm/i915/gvt/sched_policy.c | 48
> ++++++++++++++++++++++++++-------
>  1 file changed, 38 insertions(+), 10 deletions(-)
> 
> diff --git a/drivers/gpu/drm/i915/gvt/sched_policy.c
> b/drivers/gpu/drm/i915/gvt/sched_policy.c
> index c7fd8b8..04f874b 100644
> --- a/drivers/gpu/drm/i915/gvt/sched_policy.c
> +++ b/drivers/gpu/drm/i915/gvt/sched_policy.c
> @@ -190,7 +190,10 @@ static void try_to_schedule_next_vgpu(struct
> intel_gvt *gvt)
>  		wake_up(&scheduler->waitq[i]);
>  }
> 
> -static struct intel_vgpu *find_busy_vgpu(struct list_head *head,
> +#define vgpu_has_ts_limit(vgpu_data) \
> +	((vgpu_data)->allocated_ts <
> ms_to_ktime(GVT_TS_BALANCE_PERIOD_MS))
> +

I don't quite understand the meaning of this macro. either add
some comment or change to a better name.

From my understanding, looks you want to catch a vGPU which
is not scheduled in previous timeslice (in that cast the accumulated
slice would exceed 100ms, and then you want some special 
handling?)

> +static struct intel_vgpu *find_vgpu_timeslice_left(struct list_head
> +*head,
>  					struct gvt_sched_data *sched_data)  {
>  	struct vgpu_sched_data *vgpu_data;
> @@ -206,8 +209,16 @@ static struct intel_vgpu *find_busy_vgpu(struct
> list_head *head,
>  		if (!vgpu_has_pending_workload(vgpu_data->vgpu))
>  			continue;
> 
> -		vgpu = vgpu_data->vgpu;
> -		break;
> +		/* Return the vGPU if there is no time slice limitation */
> +		if (!vgpu_has_ts_limit(vgpu_data)) {
> +			vgpu = vgpu_data->vgpu;
> +			break;
> +
> +		/* Return the vGPU only if it has time slice left */
> +		} else if (vgpu_data->left_ts > 0) {
> +			vgpu = vgpu_data->vgpu;
> +			break;
> +		}

A bit confused here. Isn't it that you can always use left_ts to judge
regardless of whether allocated_ts exceeds limitation? Suppose
left_ts should be always >0 when allocated_ts>100ms...

>  	}
> 
>  	return vgpu;
> @@ -243,6 +254,9 @@ static struct intel_vgpu
> *find_longest_unsched_vgpu(struct list_head *lru_vgpu_h
>  	return NULL;
>  }
> 
> +#define is_not_idle_vgpu(vgpu) \
> +	((vgpu) && ((vgpu) != (vgpu)->gvt->idle_vgpu))

I would change to the other way:

#define is_idle_vgpu(vgpu)
	((vgpu) && ((vgpu) == (vgpu)->gvt->idle_vgpu))

Then you can use !is_idle_vgpu(vgpu) for original purpose. :-)

> +
>  static struct list_head *get_sched_head(struct gvt_sched_data *sched_data)
> {
>  	struct intel_gvt *gvt = sched_data->gvt; @@ -251,8 +265,12 @@
> static struct list_head *get_sched_head(struct gvt_sched_data *sched_data)
>  	struct list_head *head;
> 
>  	if (scheduler->current_vgpu) {
> -		cur_vgpu_data = scheduler->current_vgpu->sched_data;
> -		head = &cur_vgpu_data->list;
> +		if (is_not_idle_vgpu(scheduler->current_vgpu)) {
> +			cur_vgpu_data = scheduler->current_vgpu-
> >sched_data;
> +			head = &cur_vgpu_data->list;
> +		} else {
> +			head = &sched_data->runq_head;
> +		}
>  	} else {
>  		struct vgpu_sched_data *lru_vgpu_data;
> 
> @@ -272,6 +290,7 @@ static struct list_head *get_sched_head(struct
> gvt_sched_data *sched_data)
> 
>  static struct intel_vgpu *pickup_next_vgpu(struct gvt_sched_data
> *sched_data)  {
> +	struct intel_gvt *gvt = sched_data->gvt;
>  	struct vgpu_sched_data *next_vgpu_data;
>  	struct intel_vgpu *next_vgpu;
>  	struct list_head *head;
> @@ -297,8 +316,14 @@ static struct intel_vgpu *pickup_next_vgpu(struct
> gvt_sched_data *sched_data)
>  		list_del_init(&next_vgpu_data->list);
>  		list_add(&next_vgpu_data->list, head);
>  	} else {
> -		/* Choose the vGPU which has pending workload */
> -		next_vgpu = find_busy_vgpu(head, sched_data);
> +		/* Choose the vGPU which has timeslice left */
> +		next_vgpu = find_vgpu_timeslice_left(head, sched_data);

find_eligible_vgpu?

> +
> +		/* Switch to idle vGPU when all next candidates are
> +		 * empty.
> +		 */
> +		if (!next_vgpu)
> +			next_vgpu = gvt->idle_vgpu;
>  	}
> 
>  	return next_vgpu;
> @@ -329,9 +354,12 @@ static void tbs_sched_func(struct gvt_sched_data
> *sched_data)
>  		gvt_dbg_sched("pick next vgpu %d\n", vgpu->id);
> 
>  		/* Move the last used vGPU to the tail of lru_list */
> -		vgpu_data = vgpu->sched_data;
> -		list_del_init(&vgpu_data->lru_list);
> -		list_add_tail(&vgpu_data->lru_list, &sched_data-
> >lru_vgpu_head);
> +		if (vgpu != vgpu->gvt->idle_vgpu) {
> +			vgpu_data = vgpu->sched_data;
> +			list_del_init(&vgpu_data->lru_list);
> +			list_add_tail(&vgpu_data->lru_list,
> +					&sched_data->lru_vgpu_head);
> +		}
>  	}
>  out:
>  	if (scheduler->next_vgpu) {
> --
> 2.7.4
> 
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