[Libreoffice-bugs] [Bug 122324] New: Setting list style spacing does not make sense

bugzilla-daemon at bugs.documentfoundation.org bugzilla-daemon at bugs.documentfoundation.org
Tue Dec 25 19:58:19 UTC 2018


https://bugs.documentfoundation.org/show_bug.cgi?id=122324

            Bug ID: 122324
           Summary: Setting list style spacing does not make sense
           Product: LibreOffice
           Version: 6.1.4.2 release
          Hardware: All
                OS: All
            Status: UNCONFIRMED
          Severity: normal
          Priority: medium
         Component: Writer
          Assignee: libreoffice-bugs at lists.freedesktop.org
          Reporter: tomaskeb at gmail.com

Description:
When defining the spacing in list style, the numbers are, in my opinion,
absolutely unclear.

E.g. I want different levels to start at 0, 0.5, 1, 1.5 cm etc.
And I want the spacing between the start of the numbering/list to be always
e.g. 0.65 cm

I'd imagine just setting two numbers: the indent and the numbering width – as
in MS Word.

However, there are three numbers to input: indent, tab width, second indent
(right now I don't know the English equivalent, see screenshot).

The third number must equal the first + the second, otherwise the start of the
list text jumps at random directions and it is impossible to predict what it
will do.

I think in earlier versions this setting was more clear, but I can't remember
in which exactly…


Steps to Reproduce:
try to define a list style

Actual Results:
it is not clear how the numbers work and produce random outcomes

Expected Results:
the settings are simple, working and easy to understand


Reproducible: Always


User Profile Reset: No



Additional Info:
by the way, the 10-level system of setting the list spacing is just
exaggerated; it would be enough to include just three input fields for
everything:

1) the indent of the first level
2) the indent for each successive level (e.g. when inputting 0.5, the second
level would have the indent of the first level + 1 * 0.5, the third = first + 2
* 0.5 etc.)
3) the width of the numbering

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