[Libreoffice-bugs] [Bug 121575] Logical function IFS

[bugzilla-daemon at bugs.documentfoundation.org]

https://bugs.documentfoundation.org/show_bug.cgi?id=121575

Eike Rathke <erack at redhat.com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|UNCONFIRMED                 |RESOLVED
         Resolution|---                         |NOTABUG

--- Comment #3 from Eike Rathke <erack at redhat.com> ---
PIÙ.SE() should be IFS() (see summary).
Anyhow, conditions like  0<=Value<1  to evaluate whether Value is between [0,1)
are wrong as they evaluate as  (0<=Value)<1  which of course is not what was
intended; they would need to be expressed as AND(0<=Value;Value<1) or as
separate conditions to IFS().

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