[Libreoffice-bugs] [Bug 121575] Logical function IFS

[bugzilla-daemon at bugs.documentfoundation.org]

https://bugs.documentfoundation.org/show_bug.cgi?id=121575

--- Comment #5 from Mike Kaganski <mikekaganski at hotmail.com> ---
(In reply to Mario Cataldi from comment #4)

See what Eike said. Your formula is incorrect. This one could work:

> =IFS(A12<0;"ERROR";A12<1;"A";A12<1,5;"B";A12<3;"C";TRUE();"D")

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