[Libreoffice-bugs] [Bug 126016] falla en la ayuda de la estructura función "SI" al usar paréntesis en la zona de valor si verdadero

[bugzilla-daemon at bugs.documentfoundation.org]

https://bugs.documentfoundation.org/show_bug.cgi?id=126016

Julien Nabet <serval2412 at yahoo.fr> changed:

           What    |Removed                     |Added
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                 CC|                            |serval2412 at yahoo.fr

--- Comment #1 from Julien Nabet <serval2412 at yahoo.fr> ---
Google translate (I don't know if it's accurate or not).
Description:
if I nest some comparative function like "Y" or the function "O" or "XOR" as a
logical condition in the "if" function, and if I open a parenthesis in the
value "if true", it re-enters the comparison function , the formula works, but
it is visualized as if it were inside the comparative function, I tried with
the functions "Y" "O" "XOR", I have not tried with other functions but I assume
they have the same problem

Steps to reproduce:
1.write for example this function = yes (y (a1> 0, b1> 0), (10 * 20), "")
2. When clicking within (10 * 20) what should be the "if true" zone in the
structure of the formula appears as if it were inside the "Y" function
3. The operation is fine of the formula, but the help or the structure that
appears as a help is as if it were inside the "Y" function

Actual Results:
the operation is fine of the formula, but the help or structure appears as if
it were inside the "Y" function

Expected Results:
If I use parentheses in "value if true" despite using parentheses it should be
kept in that part of the structure of the "yes" function, the "Y" function
should not appear again because it is already closed


5.2.7 is EOL, could you give a try to a recent LO version (6.2.4)?
Also, could you explain in English for the next time.

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