[Libreoffice-bugs] [Bug 130734] COUNTIFS function not evaluating correctly when not only checking for equality

[bugzilla-daemon at bugs.documentfoundation.org]

https://bugs.documentfoundation.org/show_bug.cgi?id=130734

Eike Rathke <erack at redhat.com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
         Resolution|---                         |NOTABUG
             Status|UNCONFIRMED                 |RESOLVED

--- Comment #1 from Eike Rathke <erack at redhat.com> ---
The result 2 in A9 is correct. The formula is
=COUNTIFS($A$2:$A$5; "foo"; $B$2:$B$5;"<>''")
The Criteria "<>''" matches all cells where the content is not the literal
string '' (two consecutive appostrophes). The "''" does *not* denote an empty
string. If you wanted to match non-empty cells then the Criteria argument
should be "<>", i.e. only the <> operator without further value.

I don't recall what 5.9 may have done there, but if the result was 1 in that
case then it was wrong. There was some bug with the IFS() function.

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