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<th>Bug ID</th>
<td><a class="bz_bug_link
bz_status_UNCONFIRMED "
title="UNCONFIRMED - UI: Functions IFS does not work together with function CURRENT"
href="https://bugs.documentfoundation.org/show_bug.cgi?id=111675">111675</a>
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<th>Summary</th>
<td>UI: Functions IFS does not work together with function CURRENT
</td>
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<th>Product</th>
<td>LibreOffice
</td>
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<th>Version</th>
<td>5.3.3.2 release
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<th>Hardware</th>
<td>x86-64 (AMD64)
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<th>OS</th>
<td>Linux (All)
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<th>Status</th>
<td>UNCONFIRMED
</td>
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<th>Severity</th>
<td>normal
</td>
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<th>Priority</th>
<td>medium
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<th>Component</th>
<td>Calc
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<th>Assignee</th>
<td>libreoffice-bugs@lists.freedesktop.org
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<th>Reporter</th>
<td>michaelof@rocketmail.com
</td>
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<p>
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<pre>Description:
Using Function IFS and CURRENT within Test expressions leads to not
comprehensible results.
Target/background: A cell (referencing whatever, e.g. COUNTIF etc.) should have
a STYLE() applied, depending on another cell's value, e.g. a treshold in a real
life example
Works with nested if, does NOT WORK with IFS. Example uploaded.
Steps to Reproduce:
All in uploaded "SampleSTYLE.ods":
Both ref value B2 and Treshold value B3 are the same, e.g. 4
Actual Results:
(B5) =B2+STYLE(IFS(CURRENT()<B3;"Grün";CURRENT()=B3;"Gelb";CURRENT()>B3;"Rot"))
leads to 4 with "Rot" = RED, wrong as CURRENT()=B3 is TRUE!
(B6)
=B2+STYLE(IF(CURRENT()<B3;"Grün";IF(CURRENT()=B3;"Gelb";IF(CURRENT()>B3;"Rot"))))
leads to 4 with "Gelb" = YELLOW, correct.
Expected Results:
IFS should be able to work in combination with CURRENT
Reproducible: Always
User Profile Reset: No
Additional Info:
User-Agent: Mozilla/5.0 (X11; Linux x86_64; rv:52.0) Gecko/20100101
Firefox/52.0</pre>
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