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<th>Bug ID</th>
<td><a class="bz_bug_link
bz_status_UNCONFIRMED "
title="UNCONFIRMED - Auto_increment issue editing Base"
href="https://bugs.documentfoundation.org/show_bug.cgi?id=126639">126639</a>
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<th>Summary</th>
<td>Auto_increment issue editing Base
</td>
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<th>Product</th>
<td>LibreOffice
</td>
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<th>Version</th>
<td>6.1.2.1 release
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<th>Hardware</th>
<td>x86-64 (AMD64)
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<th>OS</th>
<td>Windows (All)
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<th>Status</th>
<td>UNCONFIRMED
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<th>Severity</th>
<td>normal
</td>
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<th>Priority</th>
<td>medium
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<th>Component</th>
<td>Base
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<th>Assignee</th>
<td>libreoffice-bugs@lists.freedesktop.org
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<th>Reporter</th>
<td>happy_hour@web.de
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<pre>Description:
I tried to create a new table in Base (actually 6.2.5, but happend also
before). I defined a primary Key with auto increment. If I don't put any other
column in the table, everything is ok. If I try to add a column, the auto
increment option is set to no - and I can't edit any setting of any column
after saving. In former versions, the auto increment worked. When I create a
table with the assistant and fill in to the auto increment option
AUTO_INCREMENT according to the help file, there occurs an error note that
AUTO_INCREMENT is unknown. If I don't write the text into the option, the
column is created with no autoincrement, despite I marked the option in the
dialogue for the primary key. If You need some screenshots, feel free to
contact me.
Steps to Reproduce:
see Description
Actual Results:
primary key is created without autoincrement, columns are not to be edited any
more
Expected Results:
autoincrement setting should be preserved even after editing columns. Columns
should be to edit after saving
Reproducible: Always
User Profile Reset: No
Additional Info:
Auto-Increment-Ausdruck
>From HELP (German Version):
Geben Sie den SQL-Befehlsparameter ein, der die Datenquelle anweist, ein
bestimmtes Integer-Datenfeld als Auto-Increment-Datenfeld zu behandeln. Der
folgende MySQL-Befehl verwendet beispielsweise den AUTO_INCREMENT-Befehl zum
Hochzählen des "id"-Feldes, wenn durch den Befehl ein Datenfeld erstellt wird:
CREATE TABLE "table1" ("id" INTEGER AUTO_INCREMENT)
Für dieses Beispiel müssen Sie AUTO_INCREMENT in das Feld Auto-Increment-Befehl
eingeben.
This throwed me an error</pre>
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