[Libreoffice-commits] help.git: Branch 'libreoffice-5-2' - source/text

[Eike Rathke]

 source/text/scalc/01/04060111.xhp |    6 +++---
 1 file changed, 3 insertions(+), 3 deletions(-)

New commits:
commit 09063ddab885bd432d09d0d2205511edbf6fe2f9
Author: Eike Rathke <erack at redhat.com>
Date:   Wed Jun 1 12:59:37 2016 +0200

    eliminate the mentioning of locale dependent date string in ISLEAPYEAR
    
    Rather use DATE() and "yyyy-mm-dd" ISO examples.
    
    Change-Id: I41c9dc57167f8c70e8674fcd4b4038ab8e835141
    (cherry picked from commit 8353d5baa0186d0774a9ddd598677b31bff5922c)
    Reviewed-on: https://gerrit.libreoffice.org/25770
    Reviewed-by: Eike Rathke <erack at redhat.com>
    Tested-by: Eike Rathke <erack at redhat.com>

diff --git a/source/text/scalc/01/04060111.xhp b/source/text/scalc/01/04060111.xhp
index 89de050..7f6950c 100644
--- a/source/text/scalc/01/04060111.xhp
+++ b/source/text/scalc/01/04060111.xhp
@@ -49,12 +49,12 @@
 <paragraph role="heading" id="hd_id3149566" xml-lang="en-US" level="2" l10n="U" oldref="14">ISLEAPYEAR</paragraph>
 <paragraph role="paragraph" id="par_id3150297" xml-lang="en-US" l10n="U" oldref="15"><ahelp hid=".">Determines whether a year is a leap year.</ahelp> If yes, the function will return the value 1 (TRUE); if not, it will return 0 (FALSE).</paragraph>
 <paragraph role="heading" id="hd_id3148487" xml-lang="en-US" level="3" l10n="U" oldref="16">Syntax</paragraph>
-<paragraph role="code" id="par_id3150205" xml-lang="en-US" l10n="U" oldref="17">ISLEAPYEAR("Date")</paragraph>
+<paragraph role="code" id="par_id3150205" xml-lang="en-US" l10n="U" oldref="17">ISLEAPYEAR(Date)</paragraph>
 <paragraph role="paragraph" id="par_id3159239" xml-lang="en-US" l10n="U" oldref="18">
-<emph>Date</emph> specifies whether a given date falls within a leap year. The Date parameter must be a valid date according to the locale settings of %PRODUCTNAME.</paragraph>
+<emph>Date</emph> specifies whether a given date falls within a leap year. The Date parameter must be a valid date.</paragraph>
 <paragraph role="heading" id="hd_id3149817" xml-lang="en-US" level="3" l10n="U" oldref="19">Example</paragraph>
 <paragraph role="paragraph" id="par_id3150786" xml-lang="en-US" l10n="CHG" oldref="20">=ISLEAPYEAR(A1) returns 1, if A1 contains 1968-02-29, the valid date 29th of February 1968 in your locale setting.</paragraph>
-<paragraph role="paragraph" id="par_idN107E7" xml-lang="en-US" l10n="CHG">You may also use =ISLEAPYEAR("1968-02-29") or =ISLEAPYEAR("2/29/68").</paragraph>
+<paragraph role="paragraph" id="par_idN107E7" xml-lang="en-US" l10n="CHG">You may also use =ISLEAPYEAR(DATE(1968;2;29)) or =ISLEAPYEAR("1968-02-29") giving the date string in the ISO 8601 notation.</paragraph>
 <paragraph role="paragraph" id="par_idN107EA" xml-lang="en-US" l10n="CHG">Never use =ISLEAPYEAR(2/29/68), because this would first evaluate 2 divided by 29 divided by 68, and then calculate the ISLEAPYEAR function from this small number as a serial date number.</paragraph>
 </section>
 <section id="years">