[Libreoffice-commits] core.git: basegfx/source

Libreoffice Gerrit user logerrit at kemper.freedesktop.org
Sat Nov 24 23:15:47 UTC 2018


 basegfx/source/polygon/b2dtrapezoid.cxx |    4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

New commits:
commit 2cc09c4650c2fc6acc0157cd26acad248f32c5ac
Author:     Andrea Gelmini <andrea.gelmini at gelma.net>
AuthorDate: Sat Nov 24 23:36:55 2018 +0100
Commit:     Julien Nabet <serval2412 at yahoo.fr>
CommitDate: Sun Nov 25 00:15:25 2018 +0100

    Fix typo
    
    Change-Id: I8e90b4592d041e63bd2efa914446db96dd293ac9
    Reviewed-on: https://gerrit.libreoffice.org/63964
    Reviewed-by: Julien Nabet <serval2412 at yahoo.fr>
    Tested-by: Julien Nabet <serval2412 at yahoo.fr>

diff --git a/basegfx/source/polygon/b2dtrapezoid.cxx b/basegfx/source/polygon/b2dtrapezoid.cxx
index 9bff42a0d0a6..9ddeed3309b9 100644
--- a/basegfx/source/polygon/b2dtrapezoid.cxx
+++ b/basegfx/source/polygon/b2dtrapezoid.cxx
@@ -588,7 +588,7 @@ namespace basegfx
             {
                 // This is the central subdivider. The strategy is to use the first two entries
                 // from the traversing edges as a potential trapezoid and do the needed corrections
-                // and adaptions on the way.
+                // and adaptations on the way.
 
                 // There always must be two edges with the same YStart value: When adding the polygons
                 // in the constructor, there is always a topmost point from which two edges start; when
@@ -661,7 +661,7 @@ namespace basegfx
                     B2DPoint aLeftEnd(aLeft.getEnd());
                     B2DPoint aRightEnd(aRight.getEnd());
 
-                    // check if end points are on the same line. If yes, no adaption
+                    // check if end points are on the same line. If yes, no adaptation
                     // needs to be prepared. Also remember which one actually is longer.
                     const bool bEndOnSameLine(fTools::equal(aLeftEnd.getY(), aRightEnd.getY()));
                     bool bLeftIsLonger(false);


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