A solution to calculation of odd roots of negative numbers with Calc
albert.thuswaldner at gmail.com
Mon Jul 16 13:30:30 PDT 2012
On Mon, Jul 16, 2012 at 10:18 PM, Ruslan Kabatsayev
<b7.10110111 at gmail.com> wrote:
> On Mon, Jul 16, 2012 at 11:13 PM, Albert Thuswaldner
> <albert.thuswaldner at gmail.com> wrote:
>> Sorry, It was a long time since I went to the university, but I if I'm
>> correct you want to calculate:
>> (-27)^(1/3) (note it is the same as 3x(-1)^(1/3) which to my mind
>> results in an complex number (not -3) thus the #VALUE!.
>> just to double check:
> Well, in fact, there're 3 roots, one of which is -3:
Ahh, you're right, sorry for the noise.
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