[Mesa-dev] [PATCH] intel/fs: Use a pure vertical stride for large register strides

Jason Ekstrand jason at jlekstrand.net
Fri Nov 10 01:01:22 UTC 2017


On Thu, Nov 9, 2017 at 2:23 PM, Matt Turner <mattst88 at gmail.com> wrote:

> On Thu, Nov 2, 2017 at 3:54 PM, Jason Ekstrand <jason at jlekstrand.net>
> wrote:
> > Register strides higher than 4 are uncommon but they can happen.  For
> > instance, if you have a 64-bit extract_u8 operation, we turn that into
> > UB -> UQ MOV with a source stride of 8.  Our previous calculation would
> > try to generate a stride of <32;8,8>:ub which is invalid because the
> > maximum horizontal stride is 4.  To solve this problem, we instead use a
> > stride of <8;1,0>.  As noted in the comment, this does not work as a
> > destination but that's ok as very few things actually generate that
> > stride.
>
> Please put the tests you fixed in the commit message. It's not okay to
> leave that out for all the reasons that I'm sure you know.
>

I didn't because the test passes before and after the patch.  I guess I
could have included that information though.


> Looks like this doesn't work on CHV, BXT, GLK :(
>
> KHR-GL46.shader_ballot_tests.ShaderBallotBitmasks now fails on CHV,
> BXT, GLK with:
>
> mov(8)          g21<1>UQ        g19<8,1,0>UB                    { align1
> 1Q };
>         ERROR: Source and destination horizontal stride must equal and
> a multiple of a qword when the execution type is 64-bit
>         ERROR: Vstride must be Width * Hstride when the execution type is
> 64-bit
>
> Modulo the typo in the first error, I think both of these are correct.
> I don't think we can extract_u8 to a 64-bit type on Atom :(
>

That's unfortunate...  Quickly racking my brain, I don't see a slick way to
implement that opcode.  How would you feel about some late opt_algebraic
lowering?


> This is filed as https://bugs.freedesktop.org/show_bug.cgi?id=103628
>
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