[Mesa-dev] [PATCH] intel/compiler: Explicitly cast register type in switch
Ian Romanick
idr at freedesktop.org
Thu Mar 29 18:32:17 UTC 2018
From: Ian Romanick <ian.d.romanick at intel.com>
brw_reg::type is "enum brw_reg_type type:4". For whatever reason, GCC
is treating this as an int instead of an enum. As a result, it doesn't
detect missing switch cases and it doesn't detect that flow can get out
of the switch.
This silences the warning:
src/intel/compiler/brw_reg.h: In function ‘bool brw_regs_negative_equal(const brw_reg*, const brw_reg*)’:
src/intel/compiler/brw_reg.h:305:1: warning: control reaches end of non-void function [-Wreturn-type]
}
^
Signed-off-by: Ian Romanick <ian.d.romanick at intel.com>
---
src/intel/compiler/brw_reg.h | 2 +-
1 file changed, 1 insertion(+), 1 deletion(-)
diff --git a/src/intel/compiler/brw_reg.h b/src/intel/compiler/brw_reg.h
index 68158cc0cc8..62f76ac0fe0 100644
--- a/src/intel/compiler/brw_reg.h
+++ b/src/intel/compiler/brw_reg.h
@@ -262,7 +262,7 @@ brw_regs_negative_equal(const struct brw_reg *a, const struct brw_reg *b)
if (a->bits != b->bits)
return false;
- switch (a->type) {
+ switch ((enum brw_reg_type) a->type) {
case BRW_REGISTER_TYPE_UQ:
case BRW_REGISTER_TYPE_Q:
return a->d64 == -b->d64;
--
2.14.3
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