what is the effect of RADEON_ALIGN (macros) in ATI-driver?

[Cui, Hunk]

Hi, Tom,

> >>> 	But I'm confused by the code, not really sure of the calculate:
> >>> YDstPitch = (width + 31) & ~31; & UVDstPitch = ((width >> 1) + 15)
&
> >>> ~15;
> >>
> >> '(variable + X) & ~X' is a common idiom to align the variable to
the
> >> next multiple of (X+1).
> >
> > 	Thank you for your hints, Could you give more explanation and
> > some example to describe it? :)
> > 	I need more info about this. :)
> 
> Some hardware requires that memory access be aligned to certain
> boundaries. Even on x86 CPUs this is true to some extent (aligned
memory
> access is faster than unaligned).
> See the description of 'unaligned access' and the example at
> http://en.wikipedia.org/wiki/Bus_error.
> http://www.alexonlinux.com/aligned-vs-unaligned-memory-access also
looks
> like a good description of what unaligned memory access is (it even
has
> pretty pictures).

	I saw your info and many thanks for your help. :) But this info
are focus on bus error, refer to CPU "aligned" to a specific boundary,
such as 16 bits (addresses 0, 2, 4 can be accessed, addresses from 1, 3,
5, are unaligned) or 32 bits (0, 4, 8, 12 are aligned, all addresses
in-between are unaligned).
	I want to know why the variable should add X (in '(variable +
X)'), what is the mainly intention? What are the different with HW
operation?

Thanks,
Hunk Cui