Bill Crawford billcrawford1970 at
Thu Apr 9 02:42:59 PDT 2009

On 04/08/2009 05:00 PM, Thomas Dickey wrote:
> > >>>If only the latest release is "API-stable", by definition it's not
> > >>>stable.

On Wed, Apr 08, 2009 at 05:34:48PM -0400, Behdad Esfahbod wrote:
> > This cannot be deduced from that line.  You need to review your math.

On Wednesday 08 April 2009 22:52:12 Thomas Dickey wrote:

> Behdad's comment doesn't make sense in English.
> (Perhaps someone can help Behdad with that - or else explain to him
> what "API-stable" might mean).

It makes perfect sense. He's saying that (f(A) ⊢ g(B)) ⊬ (¬f(A) ⊢ ¬g(B)), where 
A is "release", f is "latest", B is "API" and g is "stable" ;o)

The point is not that it has to be the "latest" release to be "stable", the 
point is that it needs to be an actual release, because between those, they 
might experiment with things and change them before release, and you don't want 
to depend on any temporary change that might be withdrawn rapidly. Over the 
longer term, sure, things get deprecated, but it's to be hoped that over quite 
a long period of time.

At least, I *think* that's what he said.

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