steve.kreyer at web.de
Sat May 26 03:44:26 PDT 2007
thanks for your answer!
Thiago Macieira wrote:
> Steve Kreyer wrote:
>> I have a question about the org.freedesktop.DBus.Introspectable
>> interface. My object supports this interface by specifying it in the
>> iface definition, and by implementing the Introspect method,
>> but if I
>> request the method on the DBus- self object, via "dbus-send
>> --print-reply --dest=org.freedesktop.DBus /org/freedesktop/DBus
>> org.freedesktop.DBus.Introspectable.Introspect", the returned string of
>> my implementation of Introspect does not appear in the reply.
> Well, that's because you're not talking to your program. If you send a
> call to dbus-daemon, it's dbus-daemon that will reply.
> What happens if you use --dest=<your-program> ?
Now Iam totally confused :-) I requested the method like you suggested:
dbus-send --print-reply --dest=my.domain.program /path/to/myobject
and the reply are the "raw interface definitions" of the interfaces
which are supported by myobject + the spec of Introspectable.Introspect.
But it seems that it doesn't care whether myobject supports and
implements the method org.freedesktop.DBus.Introspectable.Introspect
explicitly or not. So I ask myself if any object, which registers to
the bus, gets an implementation of
org.freedesktop.DBus.Introspectable.Introspect automatically in any way?
>> So should I understand the interface as a standard, so that if a
>> controller wants to get information he requests
>> org.freedesktop.DBus.Introspectable.Introspect on my object and get this
>> information? Or has it some real functional meanings inside the
>> implementation of the DBus self object?
>> I hope you understand my concern ...
> Well, no, I don't understand the questions. Please clarify.
> The org.freedesktop.DBus.Introspectable interface is an interface like any
> other. So it's a "contract" between caller and callee. Caller says "I
> will implement these methods, all of them, and each will have these
> parameters; each method or signal shall have this meaning".
> Anyone can implement an interface.
> But, no, libdbus-1 or the D-Bus protocol do not assign any special meaning
> to that interface. The only interface with special meaning is
I think this answer has satisfied my first request.
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