[Mesa-dev] [PATCH] glsl: OpenGLES GLSL 3.1 precision qualifiers ordering rules
Iago Toral
itoral at igalia.com
Mon Nov 2 23:13:56 PST 2015
On Sat, 2015-10-31 at 23:22 -0700, Jordan Justen wrote:
> On 2015-10-29 01:22:37, Iago Toral wrote:
> > On Thu, 2015-10-29 at 00:47 -0700, Jordan Justen wrote:
> > > The OpenGLES GLSL 3.1 specification uses the precision qualifier
> > > ordering rules from ARB_shading_language_420pack.
> >
> > Maybe expand the commit log to make explicit that this is for GLES 3.1
> > and desktop GL since 4.2
>
> has_420pack already checks for OpenGL 4.2, so for desktop GL, this
> patch doesn't change anything.
Oh right, I had missed that.
> I don't think we want to add OpenGLES 3.1 to has_420pack because the
> 3.1 spec doesn't appear to adopt all of 420pack.
Yeah, agreed.
Iago
> -Jordan
>
> > Reviewed-by: Iago Toral Quiroga <itoral at igalia.com>
> >
> > > Signed-off-by: Jordan Justen <jordan.l.justen at intel.com>
> > > ---
> > > src/glsl/glsl_parser.yy | 6 ++++--
> > > 1 file changed, 4 insertions(+), 2 deletions(-)
> > >
> > > diff --git a/src/glsl/glsl_parser.yy b/src/glsl/glsl_parser.yy
> > > index 2f2e10d..4636435 100644
> > > --- a/src/glsl/glsl_parser.yy
> > > +++ b/src/glsl/glsl_parser.yy
> > > @@ -948,7 +948,8 @@ parameter_qualifier:
> > > if ($2.precision != ast_precision_none)
> > > _mesa_glsl_error(&@1, state, "duplicate precision qualifier");
> > >
> > > - if (!state->has_420pack() && $2.flags.i != 0)
> > > + if (!(state->has_420pack() || state->is_version(420, 310)) &&
> > > + $2.flags.i != 0)
> > > _mesa_glsl_error(&@1, state, "precision qualifiers must come last");
> > >
> > > $$ = $2;
> > > @@ -1847,7 +1848,8 @@ type_qualifier:
> > > if ($2.precision != ast_precision_none)
> > > _mesa_glsl_error(&@1, state, "duplicate precision qualifier");
> > >
> > > - if (!state->has_420pack() && $2.flags.i != 0)
> > > + if (!(state->has_420pack() || state->is_version(420, 310)) &&
> > > + $2.flags.i != 0)
> > > _mesa_glsl_error(&@1, state, "precision qualifiers must come last");
> > >
> > > $$ = $2;
> >
> >
>
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