[Mesa-dev] [PATCH] glsl/ast: don't allow subroutine uniform comparisons
Ian Romanick
idr at freedesktop.org
Tue Jun 7 16:59:35 UTC 2016
On 06/06/2016 10:20 PM, Dave Airlie wrote:
> From: Dave Airlie <airlied at redhat.com>
>
> This fixes:
> GL45-CTS.shader_subroutine.subroutines_cannot_be_assigned_float_int_values_or_be_compared
>
> though I'm not 100% sure why this is illegal from the spec,
> but it makes us pass the test, and I really can't see a use case for this.
I think the test is wrong. Section 5.9 (Expressions) of the GLSL 4.5
spec clearly says:
The equality operators equal (==), and not equal (!=) operate on
all types (except aggregates that contain opaque types).
As much as anyone would use subroutines, you could imagine this being
used like:
value = foo(param1, param2);
if (foo != bar)
value += bar(param1, param2);
> Signged-off-by: Dave Airlie <airlied at redhat.com>
> ---
> src/compiler/glsl/ast_to_hir.cpp | 6 ++++++
> 1 file changed, 6 insertions(+)
>
> diff --git a/src/compiler/glsl/ast_to_hir.cpp b/src/compiler/glsl/ast_to_hir.cpp
> index b7192b2..fbd3256 100644
> --- a/src/compiler/glsl/ast_to_hir.cpp
> +++ b/src/compiler/glsl/ast_to_hir.cpp
> @@ -1484,6 +1484,12 @@ ast_expression::do_hir(exec_list *instructions,
> "operand of type 'void' or a right operand of type "
> "'void'", (this->oper == ast_equal) ? "==" : "!=");
> error_emitted = true;
> + } else if (op[0]->type->is_subroutine() || op[1]->type->is_subroutine()) {
> + _mesa_glsl_error(& loc, state, "`%s': wrong operand types: "
> + "no operation `%1$s' exists that takes a left-hand "
> + "operand of type 'subroutine' or a right operand of type "
> + "'subroutine'", (this->oper == ast_equal) ? "==" : "!=");
> + error_emitted = true;
> } else if ((!apply_implicit_conversion(op[0]->type, op[1], state)
> && !apply_implicit_conversion(op[1]->type, op[0], state))
> || (op[0]->type != op[1]->type)) {
>
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