[Mesa-dev] [PATCH 07/18] intel/compiler: fix for memmove argument on annotating error
Rogovin, Kevin
kevin.rogovin at intel.com
Wed Nov 15 08:13:32 UTC 2017
I have just seen that I have had an epic brain lapse on this.
The code is pretty clear, the correct value of count should be ann_count - i. This is because:
a. The value of ann_count is the value of the array size BEFORE the insert; this is clear from the code within the if (offset + ..) where it increments ann_count.
b. Since ann_count is the size before the insert, it should move the content in the open range [i, ann_count) to [i + 1, ann_count + 1); thus the number of elements is given by ann_count - i.
Changing the count to ann_count - i does the right thing, and also makes it quite clear that Matt is correct on patch 11: that it was just papering over a bug from using the wrong count value.
However, once this is done, the build does assert() on some shaders that I have; this is because it fails to understand some registers.
-Kevin
-----Original Message-----
From: Matt Turner [mailto:mattst88 at gmail.com]
Sent: Monday, November 13, 2017 11:21 PM
To: Rogovin, Kevin <kevin.rogovin at intel.com>
Cc: mesa-dev at lists.freedesktop.org
Subject: Re: [Mesa-dev] [PATCH 07/18] intel/compiler: fix for memmove argument on annotating error
On Mon, Nov 13, 2017 at 1:12 PM, Rogovin, Kevin <kevin.rogovin at intel.com> wrote:
> Hi,
>
>
> I confess I am not 100% on this code and I did educated guessing what it is trying to do; I figured it was trying to insert contents at the current index i; and that ann_count is the size -after- the insert. thus I figured the memmove is to move the half open interval [i, ann_count-1) to the half open interval [i + 1, ann_count). The number of elements in the half open range [i, ann_count - 1) is given by ann_count - i - 1.
>
> I tried changing the count from ann_count - i - 1 to ann_count - i + 1 and then the disassembler crashed in annotation on the same shaders that I have had it crash on before.
Interesting. Could you send me the shader binary? I'll take a look.
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